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 Author Topic: Check for Multiple Digits  (Read 7823 times)
techdude2007
New Member

Posts: 2

 « on: May 12, 2008, 09:45:17 PM »

I am trying to write a program that the user enters 4465 and the program checks to make sure that the same digits is not used twice in the number.  So in this case, the program would reject the number because there is 2 fours.  Any idea how to do this?
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Ralph
Ancient Guru

Posts: 544

 « Reply #1 on: May 13, 2008, 02:35:31 AM »

This program does not allow one to enter any previously entered digit:
Code:
REM  Program omision error detected by Moneo and corrected by Ralph on June 1, 2008, as remarked on below

CLS
PRINT
PRINT " This program allows entering a number with from 1 to 10 digits, but "
PRINT " it only accepts entry of digits that have not been used before"
PRINT
PRINT " Type in your number, digit by digit.  When done, press Enter ";
DIM n(20) AS INTEGER

DO
again:
k\$ = "": WHILE k\$ = "": k\$ = INKEY\$: WEND
IF k\$ = CHR\$(13) THEN EXIT DO 'new line, from Moneo's input
IF k\$ < "0" OR k\$ > "9" THEN GOTO again
i = i + 1
n(i) = VAL(k\$)
FOR j = 1 TO i - 1
IF n(j) = n(i) THEN
i = i - 1
GOTO again
END IF
NEXT j
PRINT k\$;
LOOP 'modified, due to Moneo's input

system
 « Last Edit: May 31, 2008, 04:59:08 PM by Ralph » Logged

Ralph, using QuickBASIC 4.5 and Windows XP Home Edition and Service Pack 2, with HP LaserJet 4L printer.
LPG
Member

Posts: 61

semper ubi sub ubi (always wear under wear)

 « Reply #2 on: May 13, 2008, 04:22:54 AM »

You could go like this:

Code:
CLS
PRINT "ENTER A NUMBER AND I WILL TELL YOU IF THERE ARE ANY REPEATS:";
LINE INPUT A\$
DIM NUMBERS(9) AS INTEGER
FOR B = 1 TO LEN(A\$)
IF NUMBERS(VAL(MID\$(A\$,B,1))) = 1 THEN REPEAT = 1
IF NUMBERS(VAL(MID\$(A\$,B,1))) = 0 THEN NUMBERS(VAL(MID\$(A\$,B,1))) = 1
NEXT B
IF REPEAT = 1 THEN PRINT "THE NUMBER HAS A REPEAT"
IF REPEAT = 0 THEN PRINT "THE NUMBER DOSN'T HAVE ANY REPEATS"

SYSTEM
 Logged

WHILE RPG\$ <> "complete" : make up silly excuses :WEND
Moneo
Na_th_an

Posts: 1971

 « Reply #3 on: May 28, 2008, 10:01:46 PM »

Here's a version with more error checking and complete reporting of duplicated digits.

Regards..... Moneo

''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
dim dup(0 to 9)
input "Enter series of numbers "; n\$
if n\$="" then print "Error: null entry.":system

for x=1 to len(n\$)
d\$=mid\$(n\$,x,1)
if d\$<"0" or d\$>"9" then print "Invalid digit(s) found.":system
d=val(d\$)
dup(d)=dup(d)+1
next x

for x=0 to 9
if dup(x)>1 then gotdups=1:print "digit";x;"repeated";dup(x);"times."
next x
if gotdups=0 then print "No duplicate digits found."
system
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Ralph
Ancient Guru

Posts: 544

 « Reply #4 on: May 30, 2008, 12:37:07 PM »

LPG and Moneo:
Seems as though techdude2007 has either not received any notification on any of our three posts, or that he has his answer(s) and believes that's the end of the story.  Nothing new, as I see this happen, now and then.  But, sometimes there is a valid reason for a long delay in answering...we'll see.
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Ralph, using QuickBASIC 4.5 and Windows XP Home Edition and Service Pack 2, with HP LaserJet 4L printer.
Dav
Ancient Guru

Posts: 709

 « Reply #5 on: May 30, 2008, 02:19:32 PM »

Well, here's another one ...

Quote

Entry:

INPUT "Enter a number: ", num       ' Get a number entry only
num\$ = STR\$(num)                      ' Convert it to a string

FOR s = 1 TO LEN(num\$) - 1          ' Step through string.
h\$ = MID\$(num\$, s, 1)                ' Get a nibble here...
t\$ = MID\$(num\$, s + 1, 1)          ' ...and a nibble there.
IF h\$ = t\$ THEN                         ' If both are the same,
PRINT "Duplicate! Re-enter!"    ' then say so ...
GOTO Entry                            ' ...and go back.
END IF
NEXT

PRINT "No duplicates found."        ' If you make it here, all OK.

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Moneo
Na_th_an

Posts: 1971

 « Reply #6 on: May 30, 2008, 10:39:09 PM »

Dav,

I think your solution assumes that the duplicate numbers are adjacent, like 4465. But, what if they are not adjacent, like 4654?

Regards..... Moneo
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Dav
Ancient Guru

Posts: 709

 « Reply #7 on: May 31, 2008, 12:37:44 AM »

Oops...I read the thread too quickly and failed to fully see what was asked for. My apologies to all.

- Dav
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Ralph
Ancient Guru

Posts: 544

 « Reply #8 on: May 31, 2008, 12:48:01 AM »

Hi, Moneo!  What's wrong with my proposed solution?
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Ralph, using QuickBASIC 4.5 and Windows XP Home Edition and Service Pack 2, with HP LaserJet 4L printer.
Moneo
Na_th_an

Posts: 1971

 « Reply #9 on: May 31, 2008, 04:28:58 PM »

Ralph,

The way you have it just goes into an endless loop. What happens is that the chr\$(13) is caught by the test if less than "0" or greater than "9", and thus the chr\$(13) is never seen later by the LOOP UNTIL.

If you put the test for chr\$(13) right after the INKEY line, then it works.
You can relace the LOOP UNTIL with a plain LOOP.

Regards..... Moneo

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Ralph
Ancient Guru

Posts: 544

 « Reply #10 on: May 31, 2008, 04:52:56 PM »

Moneo, you have a very discerning eye!  Thank you.  I went back and corrected my original code.  Oh, and speaking of "original", whatever happened to the OP?
 « Last Edit: May 31, 2008, 05:00:25 PM by Ralph » Logged

Ralph, using QuickBASIC 4.5 and Windows XP Home Edition and Service Pack 2, with HP LaserJet 4L printer.
Moneo
Na_th_an

Posts: 1971

 « Reply #11 on: May 31, 2008, 09:11:17 PM »

Glad to be of help, Ralph.

About the OP, who knows. He might have grabbed one of the solutions and ran.

Regards..... Moneo
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LPG
Member

Posts: 61

semper ubi sub ubi (always wear under wear)

 « Reply #12 on: June 01, 2008, 10:27:20 PM »

techdude2007 did not reply to his other post asking for a program to search inside an integer. He will have read it as he posted this topic after Ralph and I replied.
 Logged

WHILE RPG\$ <> "complete" : make up silly excuses :WEND
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