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 Author Topic: Search inside Integers  (Read 4499 times)
techdude2007
New Member

Posts: 2

 « on: May 10, 2008, 07:44:48 PM »

I need to find a function or command that will search inside an Integer.  I am trying to see how many times the number 5 would appear in, for example, 448567475.  The user enters in a number, and the computer will find how many times the number 5 is in that integer.

I tried to use the INSTR command, but it only indicates where the 1st occurance is, not the 2nd or third.

Any ideas?
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roy
Member

Posts: 33

 « Reply #1 on: May 10, 2008, 08:19:00 PM »

This may not be the shortest way but it works.
Code:
DIM a AS LONG
CLS

REM Your input routine goes here.
a = 233454535

b\$ = STR\$(a)
FOR i = 1 TO LEN(b\$)
IF VAL(MID\$(b\$, i, 1)) = 5 THEN tot = tot + 1
NEXT
PRINT "Number of fives = "; tot
SYSTEM

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Ralph
Ancient Guru

Posts: 544

 « Reply #2 on: May 11, 2008, 01:34:10 AM »

Roy, I think that your solution has the correct approach.  I don't think there is another way that would be more practical and logical.
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Ralph, using QuickBASIC 4.5 and Windows XP Home Edition and Service Pack 2, with HP LaserJet 4L printer.
LPG
Member

Posts: 61

semper ubi sub ubi (always wear under wear)

 « Reply #3 on: May 11, 2008, 01:51:04 AM »

could you do it like this?

Code:
CLS

INPUT A\$
S\$ = "5"

1 IF INSTR(A\$,S\$) <> 0 THEN : TOT = TOT + 1 : A\$ = RIGHT\$(A\$,LEN(A\$)-INSTR(A\$,S\$)) : GOTO 1

PRINT "THERE ARE ";TOT;" `"; S\$ ; "`'S"
SYSTEM

This works differently

What do you want it for?
 « Last Edit: May 11, 2008, 02:22:20 AM by LPG » Logged

WHILE RPG\$ <> "complete" : make up silly excuses :WEND
Ralph
Ancient Guru

Posts: 544

 « Reply #4 on: May 11, 2008, 03:14:41 AM »

Very ingenious LPG, I would not have thought of doing it that way!  It is certainly much quicker than the other way!
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Ralph, using QuickBASIC 4.5 and Windows XP Home Edition and Service Pack 2, with HP LaserJet 4L printer.
LPG
Member

Posts: 61

semper ubi sub ubi (always wear under wear)

 « Reply #5 on: May 12, 2008, 02:54:57 AM »

If it is inputting a sring I probably should have done this:

Code:
CLS ' 5 finder.v2

NUMBER\$ = "1234567890"
IN:
FOR B = 1 TO LEN(A\$)
NUM = 0
FOR C = 1 TO 10
IF MID\$(A\$,B,1) = MID\$(NUMBER\$,C,1) THEN NUM = 1
NEXT
IF NUM <> 1 THEN PRINT "YOU DIDN'T TYPE A NUMBER." : GOTO IN
NEXT

S\$ = "5"

1 IF INSTR(A\$,S\$) <> 0 THEN : TOT = TOT + 1 : A\$ = RIGHT\$(A\$,LEN(A\$)-INSTR(A\$,S\$)) : GOTO 1

PRINT "THERE ARE ";TOT;" ";CHR\$(34); S\$ ; CHR\$(34);"'S"
SYSTEM

this checks the user inputs a number. the previous version would count the "5"'s in a phrase.
 Logged

WHILE RPG\$ <> "complete" : make up silly excuses :WEND
Ralph
Ancient Guru

Posts: 544

 « Reply #6 on: May 12, 2008, 12:45:24 PM »

LPG:
I think that your original code is O.K., as it counts any "5" in the inputted string, whether the user enters a number or a string.  That was the OP's proposal.  Who care if one inputs a string or a number, the question is, "How many characters "5" are there in what I inputted?".  Your code answers the question correctly.
 Logged

Ralph, using QuickBASIC 4.5 and Windows XP Home Edition and Service Pack 2, with HP LaserJet 4L printer.
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