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January 22, 2022, 07:48:44 AM
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 Author Topic: Number relation puzzle  (Read 5454 times)
Zack
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Posts: 3974

 « on: February 17, 2006, 02:12:13 PM »

Take these three number sets.
Code:
Set #1:
087   010   008   053   723

Code:
Set #2:
079   017   009   040   824

Code:
Set #3:
094   071   006   010   980

Each number in each set has a distinctive name. The first number in each set is number A, the second is number B, and then C, D and finally E.
The challenge: write an equation that relates A, B, C and D, and holds true for all three sets.
Express the equation with A as the INDEPENDANT variable (alone on the left side).
E.g. A=((E*D)-B)^C   (not actual equation!)
You can write a program in FB or QB to do it (which would be hard), or just solve it on paper.
The winner is the person who gets it first. If nobody gets it in a few days, I'll post more sets to work with for the process of deduction.
Good luck!
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Agamemnus
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Posts: 3491

 « Reply #1 on: February 17, 2006, 07:16:25 PM »

A = (E+D)/C - B

It took me approximately 15 minutes. The way I solved it is looking for constraints and odd/even combinations..

....OWN3D!
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Zack
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Posts: 3974

 « Reply #2 on: February 19, 2006, 11:28:03 AM »

Good job, Aga!
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Agamemnus
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Posts: 3491

 « Reply #3 on: February 20, 2006, 10:11:48 PM »

Give me my reward then.  :evil:  :evil:  :evil:
Or another puzzle.
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Peace cannot be obtained without war. Why? If there is already peace, it is unnecessary for war. If there is no peace, there is already war."

Visit www.neobasic.net to see rubbish in all its finest.
Anonymous
Guest
 « Reply #4 on: February 21, 2006, 03:53:34 AM »

:rotfl:
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Zack
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Posts: 3974

 « Reply #5 on: February 21, 2006, 12:02:04 PM »

OK, I'll work on another puzzle. Just be patient, little boy.
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Freebasic is like QB, except it doesn't suck.
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